(x^2-5x+6)/(x^2-4)(x^2+3x+2)/(x^2-2x-3)

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Solution for (x^2-5x+6)/(x^2-4)(x^2+3x+2)/(x^2-2x-3) equation: 


D( x )

x^2-4 = 0

x^2-(2*x)-3 = 0

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x^2-(2*x)-3 = 0

x^2-(2*x)-3 = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(1*2) or x = (2-16^(1/2))/(1*2)

x = 3 or x = -1

x in (-oo:-2) U (-2:-1) U (-1:2) U (2:3) U (3:+oo)

(((x^2-(5*x)+6)/(x^2-4))*(x^2+3*x+2))/(x^2-(2*x)-3) = 0

(((x^2-5*x+6)/(x^2-4))*(x^2+3*x+2))/(x^2-2*x-3) = 0

((x^2-5*x+6)*(x^2+3*x+2))/((x^2-4)*(x^2-2*x-3)) = 0

x^2-5*x+6 = 0

x^2-5*x+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)+5)/(1*2) or x = (5-1^(1/2))/(1*2)

x = 3 or x = 2

(x-2)*(x-3) = 0

x^2+3*x+2 = 0

x^2+3*x+2 = 0

DELTA = 3^2-(1*2*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-3)/(1*2) or x = (-1^(1/2)-3)/(1*2)

x = -1 or x = -2

(x+2)*(x+1) = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(1*2) or x = (2-16^(1/2))/(1*2)

x = 3 or x = -1

(x+1)*(x-3) = 0

((x-2)*(x-3)*(x+2)*(x+1))/((x^2-4)*(x+1)*(x-3)) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+2 )

x+2 = 0 // - 2

x = -2

( x-2 )

x-2 = 0 // + 2

x = 2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -1} 

x in { -2} 

x in { 2} 

x in { 3} 

x belongs to the empty set

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